7(2x-2)=3(4x-5)+2x+1

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Solution for 7(2x-2)=3(4x-5)+2x+1 equation: 



7(2x-2)=3(4x-5)+2x+1

We move all terms to the left:

7(2x-2)-(3(4x-5)+2x+1)=0

We multiply parentheses

14x-(3(4x-5)+2x+1)-14=0



We calculate terms in parentheses: -(3(4x-5)+2x+1), so:

3(4x-5)+2x+1

We add all the numbers together, and all the variables

2x+3(4x-5)+1

We multiply parentheses

2x+12x-15+1

We add all the numbers together, and all the variables

14x-14

Back to the equation:

-(14x-14)



We get rid of parentheses

14x-14x+14-14=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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