7(2x-3)+19=4(x-8)

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Solution for 7(2x-3)+19=4(x-8) equation: 



7(2x-3)+19=4(x-8)

We move all terms to the left:

7(2x-3)+19-(4(x-8))=0

We multiply parentheses

14x-(4(x-8))-21+19=0



We calculate terms in parentheses: -(4(x-8)), so:

4(x-8)

We multiply parentheses

4x-32

Back to the equation:

-(4x-32)



We add all the numbers together, and all the variables

14x-(4x-32)-2=0

We get rid of parentheses

14x-4x+32-2=0

We add all the numbers together, and all the variables

10x+30=0

We move all terms containing x to the left, all other terms to the right

10x=-30

x=-30/10

x=-3

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