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7(2x-3)+1=2(x+2)
We move all terms to the left:
7(2x-3)+1-(2(x+2))=0
We multiply parentheses
14x-(2(x+2))-21+1=0
We calculate terms in parentheses: -(2(x+2)), so:We add all the numbers together, and all the variables
2(x+2)
We multiply parentheses
2x+4
Back to the equation:
-(2x+4)
14x-(2x+4)-20=0
We get rid of parentheses
14x-2x-4-20=0
We add all the numbers together, and all the variables
12x-24=0
We move all terms containing x to the left, all other terms to the right
12x=24
x=24/12
x=2
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