7(2x-3)+1=2(x+2)*

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Solution for 7(2x-3)+1=2(x+2)* equation: 



7(2x-3)+1=2(x+2)*

We move all terms to the left:

7(2x-3)+1-(2(x+2)*)=0

We multiply parentheses

14x-(2(x+2)*)-21+1=0



We calculate terms in parentheses: -(2(x+2)*), so:

2(x+2)*

We multiply parentheses

2x+4

Back to the equation:

-(2x+4)



We add all the numbers together, and all the variables

14x-(2x+4)-20=0

We get rid of parentheses

14x-2x-4-20=0

We add all the numbers together, and all the variables

12x-24=0

We move all terms containing x to the left, all other terms to the right

12x=24

x=24/12

x=2

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