7(2x-3)+3=2(6x-20)

Solution for 7(2x-3)+3=2(6x-20) equation:

7(2x-3)+3=2(6x-20)

We move all terms to the left:

7(2x-3)+3-(2(6x-20))=0

We multiply parentheses

14x-(2(6x-20))-21+3=0


We calculate terms in parentheses: -(2(6x-20)), so:

2(6x-20)

We multiply parentheses

12x-40

Back to the equation:

-(12x-40)


We add all the numbers together, and all the variables

14x-(12x-40)-18=0

We get rid of parentheses

14x-12x+40-18=0

We add all the numbers together, and all the variables

2x+22=0

We move all terms containing x to the left, all other terms to the right

2x=-22

x=-22/2

x=-11