7(2x-3)+6=12x+38

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Solution for 7(2x-3)+6=12x+38 equation: 



7(2x-3)+6=12x+38

We move all terms to the left:

7(2x-3)+6-(12x+38)=0

We multiply parentheses

14x-(12x+38)-21+6=0

We get rid of parentheses

14x-12x-38-21+6=0

We add all the numbers together, and all the variables

2x-53=0

We move all terms containing x to the left, all other terms to the right

2x=53

x=53/2

x=26+1/2

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