7(2x-3)-4(x-5)=8(x-1)+3

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Solution for 7(2x-3)-4(x-5)=8(x-1)+3 equation: 



7(2x-3)-4(x-5)=8(x-1)+3

We move all terms to the left:

7(2x-3)-4(x-5)-(8(x-1)+3)=0

We multiply parentheses

14x-4x-(8(x-1)+3)-21+20=0



We calculate terms in parentheses: -(8(x-1)+3), so:

8(x-1)+3

We multiply parentheses

8x-8+3

We add all the numbers together, and all the variables

8x-5

Back to the equation:

-(8x-5)



We add all the numbers together, and all the variables

10x-(8x-5)-1=0

We get rid of parentheses

10x-8x+5-1=0

We add all the numbers together, and all the variables

2x+4=0

We move all terms containing x to the left, all other terms to the right

2x=-4

x=-4/2

x=-2

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