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7(2x-3)=3(x+4)
We move all terms to the left:
7(2x-3)-(3(x+4))=0
We multiply parentheses
14x-(3(x+4))-21=0
We calculate terms in parentheses: -(3(x+4)), so:We get rid of parentheses
3(x+4)
We multiply parentheses
3x+12
Back to the equation:
-(3x+12)
14x-3x-12-21=0
We add all the numbers together, and all the variables
11x-33=0
We move all terms containing x to the left, all other terms to the right
11x=33
x=33/11
x=3
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