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7(2x-3)=5(2x+4)
We move all terms to the left:
7(2x-3)-(5(2x+4))=0
We multiply parentheses
14x-(5(2x+4))-21=0
We calculate terms in parentheses: -(5(2x+4)), so:We get rid of parentheses
5(2x+4)
We multiply parentheses
10x+20
Back to the equation:
-(10x+20)
14x-10x-20-21=0
We add all the numbers together, and all the variables
4x-41=0
We move all terms containing x to the left, all other terms to the right
4x=41
x=41/4
x=10+1/4
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