7(2x-4)+5x+28=6(3x-4)

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Solution for 7(2x-4)+5x+28=6(3x-4) equation: 



7(2x-4)+5x+28=6(3x-4)

We move all terms to the left:

7(2x-4)+5x+28-(6(3x-4))=0

We add all the numbers together, and all the variables

5x+7(2x-4)-(6(3x-4))+28=0

We multiply parentheses

5x+14x-(6(3x-4))-28+28=0



We calculate terms in parentheses: -(6(3x-4)), so:

6(3x-4)

We multiply parentheses

18x-24

Back to the equation:

-(18x-24)



We add all the numbers together, and all the variables

19x-(18x-24)=0

We get rid of parentheses

19x-18x+24=0

We add all the numbers together, and all the variables

x+24=0

We move all terms containing x to the left, all other terms to the right

x=-24

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