7(2x-4)-8x=-2(2x+5)+2

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Solution for 7(2x-4)-8x=-2(2x+5)+2 equation: 



7(2x-4)-8x=-2(2x+5)+2

We move all terms to the left:

7(2x-4)-8x-(-2(2x+5)+2)=0

We add all the numbers together, and all the variables

-8x+7(2x-4)-(-2(2x+5)+2)=0

We multiply parentheses

-8x+14x-(-2(2x+5)+2)-28=0



We calculate terms in parentheses: -(-2(2x+5)+2), so:

-2(2x+5)+2

We multiply parentheses

-4x-10+2

We add all the numbers together, and all the variables

-4x-8

Back to the equation:

-(-4x-8)



We add all the numbers together, and all the variables

6x-(-4x-8)-28=0

We get rid of parentheses

6x+4x+8-28=0

We add all the numbers together, and all the variables

10x-20=0

We move all terms containing x to the left, all other terms to the right

10x=20

x=20/10

x=2

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