7(2x-4)=3(x+5)-20

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Solution for 7(2x-4)=3(x+5)-20 equation: 



7(2x-4)=3(x+5)-20

We move all terms to the left:

7(2x-4)-(3(x+5)-20)=0

We multiply parentheses

14x-(3(x+5)-20)-28=0



We calculate terms in parentheses: -(3(x+5)-20), so:

3(x+5)-20

We multiply parentheses

3x+15-20

We add all the numbers together, and all the variables

3x-5

Back to the equation:

-(3x-5)



We get rid of parentheses

14x-3x+5-28=0

We add all the numbers together, and all the variables

11x-23=0

We move all terms containing x to the left, all other terms to the right

11x=23

x=23/11

x=2+1/11

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