7(2x-5)+11=3(x+2)+6x

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Solution for 7(2x-5)+11=3(x+2)+6x equation: 



7(2x-5)+11=3(x+2)+6x

We move all terms to the left:

7(2x-5)+11-(3(x+2)+6x)=0

We multiply parentheses

14x-(3(x+2)+6x)-35+11=0



We calculate terms in parentheses: -(3(x+2)+6x), so:

3(x+2)+6x

We add all the numbers together, and all the variables

6x+3(x+2)

We multiply parentheses

6x+3x+6

We add all the numbers together, and all the variables

9x+6

Back to the equation:

-(9x+6)



We add all the numbers together, and all the variables

14x-(9x+6)-24=0

We get rid of parentheses

14x-9x-6-24=0

We add all the numbers together, and all the variables

5x-30=0

We move all terms containing x to the left, all other terms to the right

5x=30

x=30/5

x=6

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