7(2x-5)=6(9x+8)

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Solution for 7(2x-5)=6(9x+8) equation: 



7(2x-5)=6(9x+8)

We move all terms to the left:

7(2x-5)-(6(9x+8))=0

We multiply parentheses

14x-(6(9x+8))-35=0



We calculate terms in parentheses: -(6(9x+8)), so:

6(9x+8)

We multiply parentheses

54x+48

Back to the equation:

-(54x+48)



We get rid of parentheses

14x-54x-48-35=0

We add all the numbers together, and all the variables

-40x-83=0

We move all terms containing x to the left, all other terms to the right

-40x=83

x=83/-40

x=-2+3/40

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