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7(2x-6)(x+3)=0
We multiply parentheses ..
7(+2x^2+6x-6x-18)=0
We multiply parentheses
14x^2+42x-42x-126=0
We add all the numbers together, and all the variables
14x^2-126=0
a = 14; b = 0; c = -126;
Δ = b2-4ac
Δ = 02-4·14·(-126)
Δ = 7056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{7056}=84$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-84}{2*14}=\frac{-84}{28} =-3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+84}{2*14}=\frac{84}{28} =3 $
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