7(2y+3)+3y-5=5y+2(3y+8)

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Solution for 7(2y+3)+3y-5=5y+2(3y+8) equation: 



7(2y+3)+3y-5=5y+2(3y+8)

We move all terms to the left:

7(2y+3)+3y-5-(5y+2(3y+8))=0

We add all the numbers together, and all the variables

3y+7(2y+3)-(5y+2(3y+8))-5=0

We multiply parentheses

3y+14y-(5y+2(3y+8))+21-5=0



We calculate terms in parentheses: -(5y+2(3y+8)), so:

5y+2(3y+8)

We multiply parentheses

5y+6y+16

We add all the numbers together, and all the variables

11y+16

Back to the equation:

-(11y+16)



We add all the numbers together, and all the variables

17y-(11y+16)+16=0

We get rid of parentheses

17y-11y-16+16=0

We add all the numbers together, and all the variables

6y=0

y=0/6

y=0

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