7(2y+3)-5y=6+4(2y+7)

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Solution for 7(2y+3)-5y=6+4(2y+7) equation: 



7(2y+3)-5y=6+4(2y+7)

We move all terms to the left:

7(2y+3)-5y-(6+4(2y+7))=0

We add all the numbers together, and all the variables

-5y+7(2y+3)-(6+4(2y+7))=0

We multiply parentheses

-5y+14y-(6+4(2y+7))+21=0



We calculate terms in parentheses: -(6+4(2y+7)), so:

6+4(2y+7)

determiningTheFunctionDomain
4(2y+7)+6

We multiply parentheses

8y+28+6

We add all the numbers together, and all the variables

8y+34

Back to the equation:

-(8y+34)



We add all the numbers together, and all the variables

9y-(8y+34)+21=0

We get rid of parentheses

9y-8y-34+21=0

We add all the numbers together, and all the variables

y-13=0

We move all terms containing y to the left, all other terms to the right

y=13

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