7(2y+3)=11y+18

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Solution for 7(2y+3)=11y+18 equation: 



7(2y+3)=11y+18

We move all terms to the left:

7(2y+3)-(11y+18)=0

We multiply parentheses

14y-(11y+18)+21=0

We get rid of parentheses

14y-11y-18+21=0

We add all the numbers together, and all the variables

3y+3=0

We move all terms containing y to the left, all other terms to the right

3y=-3

y=-3/3

y=-1

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