7(2y+3)=2(y-9)

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Solution for 7(2y+3)=2(y-9) equation:



7(2y+3)=2(y-9)
We move all terms to the left:
7(2y+3)-(2(y-9))=0
We multiply parentheses
14y-(2(y-9))+21=0
We calculate terms in parentheses: -(2(y-9)), so:
2(y-9)
We multiply parentheses
2y-18
Back to the equation:
-(2y-18)
We get rid of parentheses
14y-2y+18+21=0
We add all the numbers together, and all the variables
12y+39=0
We move all terms containing y to the left, all other terms to the right
12y=-39
y=-39/12
y=-3+1/4

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