7(2y+4)=3y+10

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Solution for 7(2y+4)=3y+10 equation: 



7(2y+4)=3y+10

We move all terms to the left:

7(2y+4)-(3y+10)=0

We multiply parentheses

14y-(3y+10)+28=0

We get rid of parentheses

14y-3y-10+28=0

We add all the numbers together, and all the variables

11y+18=0

We move all terms containing y to the left, all other terms to the right

11y=-18

y=-18/11

y=-1+7/11

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