7(2y-2)-5=7-3(3y-10)

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Solution for 7(2y-2)-5=7-3(3y-10) equation: 



7(2y-2)-5=7-3(3y-10)

We move all terms to the left:

7(2y-2)-5-(7-3(3y-10))=0

We multiply parentheses

14y-(7-3(3y-10))-14-5=0



We calculate terms in parentheses: -(7-3(3y-10)), so:

7-3(3y-10)

determiningTheFunctionDomain
-3(3y-10)+7

We multiply parentheses

-9y+30+7

We add all the numbers together, and all the variables

-9y+37

Back to the equation:

-(-9y+37)



We add all the numbers together, and all the variables

14y-(-9y+37)-19=0

We get rid of parentheses

14y+9y-37-19=0

We add all the numbers together, and all the variables

23y-56=0

We move all terms containing y to the left, all other terms to the right

23y=56

y=56/23

y=2+10/23

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