7(2y-2)=28

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Solution for 7(2y-2)=28 equation: 



7(2y-2)=28

We move all terms to the left:

7(2y-2)-(28)=0

We multiply parentheses

14y-14-28=0

We add all the numbers together, and all the variables

14y-42=0

We move all terms containing y to the left, all other terms to the right

14y=42

y=42/14

y=3

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