7(2y-3)+9=6(5y-2)

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Solution for 7(2y-3)+9=6(5y-2) equation: 



7(2y-3)+9=6(5y-2)

We move all terms to the left:

7(2y-3)+9-(6(5y-2))=0

We multiply parentheses

14y-(6(5y-2))-21+9=0



We calculate terms in parentheses: -(6(5y-2)), so:

6(5y-2)

We multiply parentheses

30y-12

Back to the equation:

-(30y-12)



We add all the numbers together, and all the variables

14y-(30y-12)-12=0

We get rid of parentheses

14y-30y+12-12=0

We add all the numbers together, and all the variables

-16y=0

y=0/-16

y=0

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