7(2y-3)=56

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Solution for 7(2y-3)=56 equation: 



7(2y-3)=56

We move all terms to the left:

7(2y-3)-(56)=0

We multiply parentheses

14y-21-56=0

We add all the numbers together, and all the variables

14y-77=0

We move all terms containing y to the left, all other terms to the right

14y=77

y=77/14

y=5+1/2

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