7(2y-4)=-22

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Solution for 7(2y-4)=-22 equation:



7(2y-4)=-22
We move all terms to the left:
7(2y-4)-(-22)=0
We add all the numbers together, and all the variables
7(2y-4)+22=0
We multiply parentheses
14y-28+22=0
We add all the numbers together, and all the variables
14y-6=0
We move all terms containing y to the left, all other terms to the right
14y=6
y=6/14
y=3/7

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