7(2y-4)=5

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Solution for 7(2y-4)=5 equation: 



7(2y-4)=5

We move all terms to the left:

7(2y-4)-(5)=0

We multiply parentheses

14y-28-5=0

We add all the numbers together, and all the variables

14y-33=0

We move all terms containing y to the left, all other terms to the right

14y=33

y=33/14

y=2+5/14

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