7(2y-7)=6(y+2)-5

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Solution for 7(2y-7)=6(y+2)-5 equation: 



7(2y-7)=6(y+2)-5

We move all terms to the left:

7(2y-7)-(6(y+2)-5)=0

We multiply parentheses

14y-(6(y+2)-5)-49=0



We calculate terms in parentheses: -(6(y+2)-5), so:

6(y+2)-5

We multiply parentheses

6y+12-5

We add all the numbers together, and all the variables

6y+7

Back to the equation:

-(6y+7)



We get rid of parentheses

14y-6y-7-49=0

We add all the numbers together, and all the variables

8y-56=0

We move all terms containing y to the left, all other terms to the right

8y=56

y=56/8

y=7

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