7(2z+1)=35

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Solution for 7(2z+1)=35 equation: 


Simplifying
7(2z + 1) = 35

Reorder the terms:
7(1 + 2z) = 35
(1 * 7 + 2z * 7) = 35
(7 + 14z) = 35

Solving
7 + 14z = 35

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-7' to each side of the equation.
7 + -7 + 14z = 35 + -7

Combine like terms: 7 + -7 = 0
0 + 14z = 35 + -7
14z = 35 + -7

Combine like terms: 35 + -7 = 28
14z = 28

Divide each side by '14'.
z = 2

Simplifying
z = 2

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