7(2z-2)=28

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Solution for 7(2z-2)=28 equation: 



7(2z-2)=28

We move all terms to the left:

7(2z-2)-(28)=0

We multiply parentheses

14z-14-28=0

We add all the numbers together, and all the variables

14z-42=0

We move all terms containing z to the left, all other terms to the right

14z=42

z=42/14

z=3

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