7(3+2p+1)=+3(p+1)

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Solution for 7(3+2p+1)=+3(p+1) equation: 



7(3+2p+1)=+3(p+1)

We move all terms to the left:

7(3+2p+1)-(+3(p+1))=0

We add all the numbers together, and all the variables

7(2p+4)-(+3(p+1))=0

We multiply parentheses

14p-(+3(p+1))+28=0



We calculate terms in parentheses: -(+3(p+1)), so:

+3(p+1)

determiningTheFunctionDomain
3(p+1)

We multiply parentheses

3p+3

Back to the equation:

-(3p+3)



We get rid of parentheses

14p-3p-3+28=0

We add all the numbers together, and all the variables

11p+25=0

We move all terms containing p to the left, all other terms to the right

11p=-25

p=-25/11

p=-2+3/11

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