7(3+2p+1)=+3(p+1)

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Solution for 7(3+2p+1)=+3(p+1) equation:



7(3+2p+1)=+3(p+1)
We move all terms to the left:
7(3+2p+1)-(+3(p+1))=0
We add all the numbers together, and all the variables
7(2p+4)-(+3(p+1))=0
We multiply parentheses
14p-(+3(p+1))+28=0
We calculate terms in parentheses: -(+3(p+1)), so:
+3(p+1)
determiningTheFunctionDomain 3(p+1)
We multiply parentheses
3p+3
Back to the equation:
-(3p+3)
We get rid of parentheses
14p-3p-3+28=0
We add all the numbers together, and all the variables
11p+25=0
We move all terms containing p to the left, all other terms to the right
11p=-25
p=-25/11
p=-2+3/11

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