7(3+2x+4x)=10(5x+3)-1

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Solution for 7(3+2x+4x)=10(5x+3)-1 equation: 



7(3+2x+4x)=10(5x+3)-1

We move all terms to the left:

7(3+2x+4x)-(10(5x+3)-1)=0

We add all the numbers together, and all the variables

7(6x+3)-(10(5x+3)-1)=0

We multiply parentheses

42x-(10(5x+3)-1)+21=0



We calculate terms in parentheses: -(10(5x+3)-1), so:

10(5x+3)-1

We multiply parentheses

50x+30-1

We add all the numbers together, and all the variables

50x+29

Back to the equation:

-(50x+29)



We get rid of parentheses

42x-50x-29+21=0

We add all the numbers together, and all the variables

-8x-8=0

We move all terms containing x to the left, all other terms to the right

-8x=8

x=8/-8

x=-1

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