7(3+4y)=15y+73

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Solution for 7(3+4y)=15y+73 equation: 



7(3+4y)=15y+73

We move all terms to the left:

7(3+4y)-(15y+73)=0

We add all the numbers together, and all the variables

7(4y+3)-(15y+73)=0

We multiply parentheses

28y-(15y+73)+21=0

We get rid of parentheses

28y-15y-73+21=0

We add all the numbers together, and all the variables

13y-52=0

We move all terms containing y to the left, all other terms to the right

13y=52

y=52/13

y=4

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