7(3+5x)=(4-x)5

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Solution for 7(3+5x)=(4-x)5 equation: 



7(3+5x)=(4-x)5

We move all terms to the left:

7(3+5x)-((4-x)5)=0

We add all the numbers together, and all the variables

7(5x+3)-((-1x+4)5)=0

We multiply parentheses

35x-((-1x+4)5)+21=0



We calculate terms in parentheses: -((-1x+4)5), so:

(-1x+4)5

We multiply parentheses

-5x+20

Back to the equation:

-(-5x+20)



We get rid of parentheses

35x+5x-20+21=0

We add all the numbers together, and all the variables

40x+1=0

We move all terms containing x to the left, all other terms to the right

40x=-1

x=-1/40

x=-1/40

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