7(3+c)=28

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Solution for 7(3+c)=28 equation: 



7(3+c)=28

We move all terms to the left:

7(3+c)-(28)=0

We add all the numbers together, and all the variables

7(c+3)-28=0

We multiply parentheses

7c+21-28=0

We add all the numbers together, and all the variables

7c-7=0

We move all terms containing c to the left, all other terms to the right

7c=7

c=7/7

c=1

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