7(3+c)=6(2+c)

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Solution for 7(3+c)=6(2+c) equation: 



7(3+c)=6(2+c)

We move all terms to the left:

7(3+c)-(6(2+c))=0

We add all the numbers together, and all the variables

7(c+3)-(6(c+2))=0

We multiply parentheses

7c-(6(c+2))+21=0



We calculate terms in parentheses: -(6(c+2)), so:

6(c+2)

We multiply parentheses

6c+12

Back to the equation:

-(6c+12)



We get rid of parentheses

7c-6c-12+21=0

We add all the numbers together, and all the variables

c+9=0

We move all terms containing c to the left, all other terms to the right

c=-9

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