7(3+c)=6(c-2)

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Solution for 7(3+c)=6(c-2) equation:


Simplifying
7(3 + c) = 6(c + -2)
(3 * 7 + c * 7) = 6(c + -2)
(21 + 7c) = 6(c + -2)

Reorder the terms:
21 + 7c = 6(-2 + c)
21 + 7c = (-2 * 6 + c * 6)
21 + 7c = (-12 + 6c)

Solving
21 + 7c = -12 + 6c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-6c' to each side of the equation.
21 + 7c + -6c = -12 + 6c + -6c

Combine like terms: 7c + -6c = 1c
21 + 1c = -12 + 6c + -6c

Combine like terms: 6c + -6c = 0
21 + 1c = -12 + 0
21 + 1c = -12

Add '-21' to each side of the equation.
21 + -21 + 1c = -12 + -21

Combine like terms: 21 + -21 = 0
0 + 1c = -12 + -21
1c = -12 + -21

Combine like terms: -12 + -21 = -33
1c = -33

Divide each side by '1'.
c = -33

Simplifying
c = -33

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