7(3-(5+2x)-2x)=-16+2(1-8x)

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Solution for 7(3-(5+2x)-2x)=-16+2(1-8x) equation: 



7(3-(5+2x)-2x)=-16+2(1-8x)

We move all terms to the left:

7(3-(5+2x)-2x)-(-16+2(1-8x))=0

We add all the numbers together, and all the variables

7(3-(2x+5)-2x)-(-16+2(-8x+1))=0



We calculate terms in parentheses: -(-16+2(-8x+1)), so:

-16+2(-8x+1)

determiningTheFunctionDomain
2(-8x+1)-16

We multiply parentheses

-16x+2-16

We add all the numbers together, and all the variables

-16x-14

Back to the equation:

-(-16x-14)



We get rid of parentheses

7(3-(2x+5)-2x)+16x+14=0

We add all the numbers together, and all the variables

16x+7(3-(2x+5)-2x)+14=0

We move all terms containing x to the left, all other terms to the right

16x+7(3-(2x+5)-2x)=-14

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