7(3-)=8(4-2x)

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Solution for 7(3-)=8(4-2x) equation: 



7(3-)=8(4-2x)

We move all terms to the left:

7(3-)-(8(4-2x))=0

We add all the numbers together, and all the variables

-(8(-2x+4))+70=0



We calculate terms in parentheses: -(8(-2x+4)), so:

8(-2x+4)

We multiply parentheses

-16x+32

Back to the equation:

-(-16x+32)



We get rid of parentheses

16x-32+70=0

We add all the numbers together, and all the variables

16x+38=0

We move all terms containing x to the left, all other terms to the right

16x=-38

x=-38/16

x=-2+3/8

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