7(3-2k)=9(k-5)

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Solution for 7(3-2k)=9(k-5) equation: 



7(3-2k)=9(k-5)

We move all terms to the left:

7(3-2k)-(9(k-5))=0

We add all the numbers together, and all the variables

7(-2k+3)-(9(k-5))=0

We multiply parentheses

-14k-(9(k-5))+21=0



We calculate terms in parentheses: -(9(k-5)), so:

9(k-5)

We multiply parentheses

9k-45

Back to the equation:

-(9k-45)



We get rid of parentheses

-14k-9k+45+21=0

We add all the numbers together, and all the variables

-23k+66=0

We move all terms containing k to the left, all other terms to the right

-23k=-66

k=-66/-23

k=2+20/23

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