7(3-2x)-(3-4x)=2x-(4x+6)

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Solution for 7(3-2x)-(3-4x)=2x-(4x+6) equation: 



7(3-2x)-(3-4x)=2x-(4x+6)

We move all terms to the left:

7(3-2x)-(3-4x)-(2x-(4x+6))=0

We add all the numbers together, and all the variables

7(-2x+3)-(-4x+3)-(2x-(4x+6))=0

We multiply parentheses

-14x-(-4x+3)-(2x-(4x+6))+21=0

We get rid of parentheses

-14x+4x-(2x-(4x+6))-3+21=0



We calculate terms in parentheses: -(2x-(4x+6)), so:

2x-(4x+6)

We get rid of parentheses

2x-4x-6

We add all the numbers together, and all the variables

-2x-6

Back to the equation:

-(-2x-6)



We add all the numbers together, and all the variables

-10x-(-2x-6)+18=0

We get rid of parentheses

-10x+2x+6+18=0

We add all the numbers together, and all the variables

-8x+24=0

We move all terms containing x to the left, all other terms to the right

-8x=-24

x=-24/-8

x=+3

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