7(3-4q)-10(q-2)=19(5-2q)

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Solution for 7(3-4q)-10(q-2)=19(5-2q) equation: 


Simplifying
7(3 + -4q) + -10(q + -2) = 19(5 + -2q)
(3 * 7 + -4q * 7) + -10(q + -2) = 19(5 + -2q)
(21 + -28q) + -10(q + -2) = 19(5 + -2q)

Reorder the terms:
21 + -28q + -10(-2 + q) = 19(5 + -2q)
21 + -28q + (-2 * -10 + q * -10) = 19(5 + -2q)
21 + -28q + (20 + -10q) = 19(5 + -2q)

Reorder the terms:
21 + 20 + -28q + -10q = 19(5 + -2q)

Combine like terms: 21 + 20 = 41
41 + -28q + -10q = 19(5 + -2q)

Combine like terms: -28q + -10q = -38q
41 + -38q = 19(5 + -2q)
41 + -38q = (5 * 19 + -2q * 19)
41 + -38q = (95 + -38q)

Add '38q' to each side of the equation.
41 + -38q + 38q = 95 + -38q + 38q

Combine like terms: -38q + 38q = 0
41 + 0 = 95 + -38q + 38q
41 = 95 + -38q + 38q

Combine like terms: -38q + 38q = 0
41 = 95 + 0
41 = 95

Solving
41 = 95

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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