7(3-5x)=4(3x-2)-6(7+9x)

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Solution for 7(3-5x)=4(3x-2)-6(7+9x) equation: 



7(3-5x)=4(3x-2)-6(7+9x)

We move all terms to the left:

7(3-5x)-(4(3x-2)-6(7+9x))=0

We add all the numbers together, and all the variables

7(-5x+3)-(4(3x-2)-6(9x+7))=0

We multiply parentheses

-35x-(4(3x-2)-6(9x+7))+21=0



We calculate terms in parentheses: -(4(3x-2)-6(9x+7)), so:

4(3x-2)-6(9x+7)

We multiply parentheses

12x-54x-8-42

We add all the numbers together, and all the variables

-42x-50

Back to the equation:

-(-42x-50)



We get rid of parentheses

-35x+42x+50+21=0

We add all the numbers together, and all the variables

7x+71=0

We move all terms containing x to the left, all other terms to the right

7x=-71

x=-71/7

x=-10+1/7

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