7(3-d)=2(9d+3)

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Solution for 7(3-d)=2(9d+3) equation: 



7(3-d)=2(9d+3)

We move all terms to the left:

7(3-d)-(2(9d+3))=0

We add all the numbers together, and all the variables

7(-1d+3)-(2(9d+3))=0

We multiply parentheses

-7d-(2(9d+3))+21=0



We calculate terms in parentheses: -(2(9d+3)), so:

2(9d+3)

We multiply parentheses

18d+6

Back to the equation:

-(18d+6)



We get rid of parentheses

-7d-18d-6+21=0

We add all the numbers together, and all the variables

-25d+15=0

We move all terms containing d to the left, all other terms to the right

-25d=-15

d=-15/-25

d=3/5

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