7(3-y)=-3(y+3)

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Solution for 7(3-y)=-3(y+3) equation: 



7(3-y)=-3(y+3)

We move all terms to the left:

7(3-y)-(-3(y+3))=0

We add all the numbers together, and all the variables

7(-1y+3)-(-3(y+3))=0

We multiply parentheses

-7y-(-3(y+3))+21=0



We calculate terms in parentheses: -(-3(y+3)), so:

-3(y+3)

We multiply parentheses

-3y-9

Back to the equation:

-(-3y-9)



We get rid of parentheses

-7y+3y+9+21=0

We add all the numbers together, and all the variables

-4y+30=0

We move all terms containing y to the left, all other terms to the right

-4y=-30

y=-30/-4

y=7+1/2

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