7(3-z)+z=5-2z

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Solution for 7(3-z)+z=5-2z equation: 



7(3-z)+z=5-2z

We move all terms to the left:

7(3-z)+z-(5-2z)=0

We add all the numbers together, and all the variables

7(-1z+3)+z-(-2z+5)=0

We add all the numbers together, and all the variables

z+7(-1z+3)-(-2z+5)=0

We multiply parentheses

z-7z-(-2z+5)+21=0

We get rid of parentheses

z-7z+2z-5+21=0

We add all the numbers together, and all the variables

-4z+16=0

We move all terms containing z to the left, all other terms to the right

-4z=-16

z=-16/-4

z=+4

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