7(3-z)/6=-7

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Solution for 7(3-z)/6=-7 equation: 



7(3-z)/6=-7

We move all terms to the left:

7(3-z)/6-(-7)=0

We add all the numbers together, and all the variables

7(-1z+3)/6-(-7)=0

We add all the numbers together, and all the variables

7(-1z+3)/6+7=0

We multiply all the terms by the denominator


7(-1z+3)+7*6=0

We add all the numbers together, and all the variables

7(-1z+3)+42=0

We multiply parentheses

-7z+21+42=0

We add all the numbers together, and all the variables

-7z+63=0

We move all terms containing z to the left, all other terms to the right

-7z=-63

z=-63/-7

z=+9

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