7(3a+4)=11(1-1)+19

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Solution for 7(3a+4)=11(1-1)+19 equation: 



7(3a+4)=11(1-1)+19

We move all terms to the left:

7(3a+4)-(11(1-1)+19)=0

We add all the numbers together, and all the variables

7(3a+4)-(110+19)=0

We add all the numbers together, and all the variables

7(3a+4)-129=0

We multiply parentheses

21a+28-129=0

We add all the numbers together, and all the variables

21a-101=0

We move all terms containing a to the left, all other terms to the right

21a=101

a=101/21

a=4+17/21

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