7(3a+4)=11(a-1)

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Solution for 7(3a+4)=11(a-1) equation: 



7(3a+4)=11(a-1)

We move all terms to the left:

7(3a+4)-(11(a-1))=0

We multiply parentheses

21a-(11(a-1))+28=0



We calculate terms in parentheses: -(11(a-1)), so:

11(a-1)

We multiply parentheses

11a-11

Back to the equation:

-(11a-11)



We get rid of parentheses

21a-11a+11+28=0

We add all the numbers together, and all the variables

10a+39=0

We move all terms containing a to the left, all other terms to the right

10a=-39

a=-39/10

a=-3+9/10

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