7(3a+4)=11(a-7)-1

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Solution for 7(3a+4)=11(a-7)-1 equation: 



7(3a+4)=11(a-7)-1

We move all terms to the left:

7(3a+4)-(11(a-7)-1)=0

We multiply parentheses

21a-(11(a-7)-1)+28=0



We calculate terms in parentheses: -(11(a-7)-1), so:

11(a-7)-1

We multiply parentheses

11a-77-1

We add all the numbers together, and all the variables

11a-78

Back to the equation:

-(11a-78)



We get rid of parentheses

21a-11a+78+28=0

We add all the numbers together, and all the variables

10a+106=0

We move all terms containing a to the left, all other terms to the right

10a=-106

a=-106/10

a=-10+3/5

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