7(3b-4)=-2b+8

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Solution for 7(3b-4)=-2b+8 equation: 



7(3b-4)=-2b+8

We move all terms to the left:

7(3b-4)-(-2b+8)=0

We multiply parentheses

21b-(-2b+8)-28=0

We get rid of parentheses

21b+2b-8-28=0

We add all the numbers together, and all the variables

23b-36=0

We move all terms containing b to the left, all other terms to the right

23b=36

b=36/23

b=1+13/23

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